(x-2)^2/3+1=5

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Solution for (x-2)^2/3+1=5 equation:


x in (-oo:+oo)

((x-2)^2)/3+1 = 5 // - 5

((x-2)^2)/3-5+1 = 0

((x-2)^2)/3+(-5*3)/3+(1*3)/3 = 0

(x-2)^2-5*3+1*3 = 0

x^2-4*x-11+3 = 0

x^2-4*x-8 = 0

x^2-4*x-8 = 0

x^2-4*x-8 = 0

DELTA = (-4)^2-(-8*1*4)

DELTA = 48

DELTA > 0

x = (48^(1/2)+4)/(1*2) or x = (4-48^(1/2))/(1*2)

x = (4*3^(1/2)+4)/2 or x = (4-4*3^(1/2))/2

(x-((4-4*3^(1/2))/2))*(x-((4*3^(1/2)+4)/2)) = 0

((x-((4-4*3^(1/2))/2))*(x-((4*3^(1/2)+4)/2)))/3 = 0

((x-((4-4*3^(1/2))/2))*(x-((4*3^(1/2)+4)/2)))/3 = 0 // * 3

(x-((4-4*3^(1/2))/2))*(x-((4*3^(1/2)+4)/2)) = 0

( x-((4*3^(1/2)+4)/2) )

x-((4*3^(1/2)+4)/2) = 0 // + (4*3^(1/2)+4)/2

x = (4*3^(1/2)+4)/2

( x-((4-4*3^(1/2))/2) )

x-((4-4*3^(1/2))/2) = 0 // + (4-4*3^(1/2))/2

x = (4-4*3^(1/2))/2

x in { (4*3^(1/2)+4)/2, (4-4*3^(1/2))/2 }

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